Suppose an astronomer discovers a distant quasar whose recessional velocity is 1/3 the speed of light. If the Hubble constant is 73 km/s/Mpc, how far away is the quasar?

Question

Quizplus · Accepted Answer

We can use the formula v=H0*d, where v is the recessional velocity, H0 is the Hubble constant, and d is the distance to the object. Rearranging the formula to solve for d, we get d=v/H0. Plugging in the given values, we get d=(1/3c)/(73 km/s/Mpc) = 1,020 Mpc. Therefore, the closest answer choice is B, 1370 Mpc, which is the rounded closest answer to 1,020 Mpc.

Suppose an Astronomer Discovers a Distant Quasar Whose Recessional Velocity