The half-life for the decay of ²⁶Al into ²⁶Mg is 720,000 years. Suppose a meteorite was formed 4.6 billion years ago that contained ²⁶Al. How much ²⁶Al does it contain now? A)almost all of its original amount B)half of its original amount C)1/6389 of its original amount D)almost none

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The half-life of ²⁶Al is 720,000 years, meaning the amount of ²⁶Al halves every 720,000 years. Over 4.6 billion years, this process would have occurred approximately 6389 times (4.6 billion / 720,000), leaving almost none of the original ²⁶Al.

The Half-Life for the Decay of 26Al into 26Mg Is

The Half-Life for the Decay of ²⁶Al into ²⁶Mg Is