According to Kepler's law, the approximate sidereal period of an asteroid moving around the Sun at a distance of about 2.8 au in the asteroid belt is:

Question

Quizplus · Accepted Answer

Kepler's third law states that the square of the orbital period of a planet is directly proportional to the cube of the semi-major axis of its orbit. This can be simplified to $T^2 = a^3$, where $T$ is the orbital period in Earth years and $a$ is the semi-major axis in astronomical units (AU). For an asteroid at 2.8 AU, the calculation would be $T^2 = 2.8^3$. Solving for $T$ gives an approximate value of 4.68 years, making option D correct.

According to Kepler's Law, the Approximate Sidereal Period of an Asteroid