Suppose that I have a sample of 25 women and they spend an average of $100 a week dining out, with a standard deviation of $20. Create a 95% confidence interval for the mean and wrap words around your results.

Question

Quizplus · Accepted Answer

The Answer is CI₉₅ = 100 +/- (4)(2.064)

\rightarrow

100 +/- 8.26

\rightarrow

91.74, 108.26. We are 95% confident that the population mean is in this interval.

Suppose That I Have a Sample of 25 Women and They