Trichloromethane, CHCl3, and Propanone, C3H6O, Form Liquid-Vapour Mixtures with a Maximum-Boiling
Trichloromethane, CHCl3, and propanone, C3H6O, form liquid-vapour mixtures with a maximum-boiling azeotrope. What does this imply about the nature of the interactions between the molecules in the mixture?
A) Strong interactions between molecules make it more difficult for them to escape from the liquid to the vapour phase.
B) The interactions between the molecules in the mixture are the same strength as those of the pure components.
C) Weak interactions between the molecules increase the vapour pressure.
D) It is not possible to infer anything about the nature of the interactions.
Correct Answer:
Verified
Q5: The vapour pressure of pure 1-propanol is
Q6: The vapour pressure of pure benzene is
Q7: The Henry's law constant for nitrogen dissolved
Q8: What is the osmotic pressure generated at
Q9: Determine the mass of potassium chloride, KCl,
Q11: Determine the vapour pressure of n-hexane, C6H14,
Q12: Determine the vapour pressure of toluene, C7H8,
Q13: Determine the vapour pressure of acetone, C3H6O,
Q14: Estimate the increase in the vapour pressure
Q15: Estimate the change in the vapour
Unlock this Answer For Free Now!
View this answer and more for free by performing one of the following actions
Scan the QR code to install the App and get 2 free unlocks
Unlock quizzes for free by uploading documents