Determine the change in standard Gibbs energy at 298 K for the reaction
PbO₂ (s) + Pb (s) + 2 H₂SO₄ (aq) → 2 PbSO₄ (aq) + 2 H₂O (l)
Which this basis of the lead-acid battery.

Question

Determine the change in standard Gibbs energy at 298 K for the reaction PbO₂ (s) + Pb (s) + 2 H₂SO₄ (aq) → 2 PbSO₄ (aq) + 2 H₂O (l) Which this basis of the lead-acid battery.

Quizplus · Accepted Answer

The correct answer is A because the change in standard Gibbs energy for the reaction is -394 kJ mol^-1. This can be calculated using the standard Gibbs energy of formation of the reactants and products.

Determine the Change in Standard Gibbs Energy at 298 K