Calculate the entropy change ( $\triangle_{fus} S^{∘}$ , J K^-1 mol^-1) when 1.00 mol of methane at its melting point (T_m = - 182.05 °C) freezes (in the process the temperature does not change and $\triangle_{fus} H^{∘}$ for methane is + 0.94 kJ mol^-1).

Question

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The entropy change upon freezing is given by:$$	riangle_{fus} S^{∘} = \frac{	riangle_{fus} H^{∘}}{T_m}$$Substituting the given values:$$	riangle_{fus} S^{∘} = \frac{0.94 \ kJ \ mol^{-1}}{182.05 \ K} = -10.3 \ J \ K^{-1} \ mol^{-1}$$

Calculate the Entropy Change △fusS∘\triangle_{fus} S^{∘}△fus​S∘ , J K-1 Mol-1) When 1

Calculate the Entropy Change $\triangle_{fus} S^{∘}$ , J K^-1 Mol^-1) When 1