The combustion of ethanol (C₂H₅OH) at 1 bar and 298 K releases 1367 kJ mol^-1 of heat.
C₂H₅OH (l) + 3 O₂ (g) $\rightarrow$ 2 CO₂ (g) + 3 H₂O (l) Calculate the standard enthalpy change of formation of ethanol (in kJ mol^-1) . Use $\Delta_{\mathrm{f}} H_{208}^{\circ}$ data in Appendix 7.

Question

The combustion of ethanol (C₂H₅OH) at 1 bar and 298 K releases 1367 kJ mol^-1 of heat.
C₂H₅OH (l) + 3 O₂ (g)

\rightarrow

2 CO₂ (g) + 3 H₂O (l) Calculate the standard enthalpy change of formation of ethanol (in kJ mol^-1) . Use

\Delta_{\mathrm{f}} H_{208}^{\circ}

data in Appendix 7.

Quizplus · Accepted Answer

The standard enthalpy change of formation of ethanol can be calculated using the enthalpy change of the combustion reaction and the standard enthalpies of formation of the products and reactants. The correct answer is -277.4 kJ/mol.

The Combustion of Ethanol (C2H5OH) at 1 Bar and 298 →\rightarrow→

The Combustion of Ethanol (C₂H₅OH) at 1 Bar and 298 $\rightarrow$