A standard solution of potassium chloride of concentration 12.5 mg dm⁻³was diluted to prepare the solutions shown. Each solution was injected into an atomic emission spectrometer and the emission intensity as shown in the table.
$\begin{array}{llllll}\hline\left[\mathrm{K}^{+}\right] / \mathrm{mg} \mathrm{dm}^{-3} & 2.50 & 5.00 & 7.50 & 10.0 & 12.5 \\\text { Emission intensity / } & 131 & 263 & 394 & 525 & 656 \\\text { arbitrary units } & & & & & \\\hline\end{array}$

Question

A standard solution of potassium chloride of concentration 12.5 mg dm⁻³was diluted to prepare the solutions shown. Each solution was injected into an atomic emission spectrometer and the emission intensity as shown in the table.

\begin{array}{llllll}\hline\left[\mathrm{K}^{+}\right] / \mathrm{mg} \mathrm{dm}^{-3} & 2.50 & 5.00 & 7.50 & 10.0 & 12.5 \\\text { Emission intensity / } & 131 & 263 & 394 & 525 & 656 \\\text { arbitrary units } & & & & & \\\hline\end{array}

Quizplus · Accepted Answer

The correct answer is A because the emission intensity is directly proportional to the concentration of the analyte. The emission intensity for 12.5 mg dm⁻³ is 656 arbitrary units, so the emission intensity for 600 ppm (which is equivalent to 600 mg dm⁻³) would be 600/12.5 * 656 = 32800 arbitrary units.

A Standard Solution of Potassium Chloride of Concentration 12 A) 600 Ppm B) 167 Ppm C) 610 Ppb D)

A Standard Solution of Potassium Chloride of Concentration 12 A) 600 Ppm
B) 167 Ppm
C) 610 Ppb
D)