For the following reaction: 2 NH₃ (g) $\rightarrow$N₂ (g) + 3 H₂ (g), the rate of consumption of ammonia was measured as 2 mmol dm^-3 s^-1; what was the rate of formation of H₂?

Question

Quizplus · Accepted Answer

From the balanced equation, we can see that 2 moles of NH₃ reacts with 3 moles of H₂ to form 1 mole of N₂ and 3 moles of ammonia. Therefore, the rate of formation of H₂ (which is the same as the rate of consumption of NH₃) is (2/3) * rate of ammonia consumption. Plugging in the given value, we get (2/3) * 2 mmol dm^-3 s^-1 = 1.33 mmol dm^-3 s^-1. Rounding off, we get B as the correct answer.

For the Following Reaction: 2 NH3 (G) →\rightarrow→ N2 (G) + 3 H2 (G), the Rate of Consumption

For the Following Reaction: 2 NH₃ (G) $\rightarrow$ N₂ (G) + 3 H₂ (G), the Rate of Consumption