A first order rate constant, k = 3.75 × 10^-2 s^-1. What is the reaction's half-life, $t_{1 / 2}$ ?

Name: A first order rate constant, k = 3.75 × 10 -2 s -1 . What is the reaction's half-life, $t_{1 / 2}$ ?
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Question

Quizplus · Accepted Answer

The half-life of a first-order reaction is given by the equation $t_{1 / 2} = \frac{ln 2}{k}$. Substituting the given value of k into this equation, we get:$t_{1 / 2} = \frac{ln 2}{3.75 × 10^{-2} s^{-1}} = 18.48 s$

A First Order Rate Constant, K = 3 t1/2t_{1 / 2}t1/2​

A First Order Rate Constant, K = 3 $t_{1 / 2}$