In the Following Reaction Sequence the First Step Is Reversible $A \longrightarrow \frac{k_{r 1}}{k_{r-1}} \longrightarrow$

In the following reaction sequence the first step is reversible. $A \longrightarrow \frac{k_{r 1}}{k_{r-1}} \longrightarrow$ $B \stackrel{k_{2}}{\longrightarrow} C$ and k₂ is small relative to k₁ and k_-1. Select all that apply.

A) $\frac{k_{-1}}{k_{1}}=K_{e}$ where K_c is the equilibrium constant.
B) The rate-determining step is step two: $B \stackrel{k_{2}}{\longrightarrow} C$ .
C) $\text { The rate of reaction }=k_{2} \frac{k_{1}}{k_{-1}}[\mathrm{~A}]$ .
D) $\text { The rate of reaction }=-\frac{d[A]}{d t}$ .