A 28.0 dm³ gas cylinder at 5.2 atm and 23 °C contains only carbon monoxide gas. What is the mass (in kg) of carbon monoxide in the tank?

Question

Quizplus · Accepted Answer

We can first use the Ideal Gas Law to determine the number of moles of carbon monoxide in the tank:

PV = nRT

P = 5.2 atm  (convert to kPa: 5.2 atm × 101.3 kPa/atm = 527.6 kPa)
V = 28.0 dm^3 (convert to m^3: 28.0 dm^3 ÷ 1000 dm^3/m^3 = 0.0280 m^3)
n = ?
R = 8.31 J/(mol·K)
T = 23°C + 273.15 = 296.15 K

527.6 kPa × 0.0280 m^3 = n × 8.31 J/(mol·K) × 296.15 K

n = 0.541 mol

Next, we can use the molar mass of carbon monoxide (28.01 g/mol) to convert from moles to grams:

0.541 mol × 28.01 g/mol = 15.1 g

Finally, we can convert from grams to kilograms:

15.1 g ÷ 1000 g/kg = 0.0151 kg

Therefore, the mass of carbon monoxide in the tank is 0.0151 kg, which corresponds to answer choice B.

A 280 Dm3 Gas Cylinder at 5

A 280 Dm³ Gas Cylinder at 5