Draw the molecular orbital diagram of OF⁺ to determine the bond order. OF⁺ can exist.

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Quizplus · Accepted Answer

To draw the molecular orbital diagram, we first need to determine the electron configuration of each atom: O: 1s² 2s² 2p⁴ F: 1s² 2s² 2p⁵ S: 1s² 2s² 2p⁶ 3s² 3p⁴ We can then combine these configurations to form molecular orbitals: - The 1s orbitals do not interact significantly with the other orbitals, so we can leave them out of the diagram. - The 2s orbitals and the 2p orbitals of O and F can interact to form six molecular orbitals (3 bonding and 3 antibonding). - The 3s orbitals and the 3p orbitals of S can interact to form eight molecular orbitals (4 bonding and 4 antibonding). The resulting diagram looks like this: ↑↑* ↑↑* ↑↑ ↑↑ O2s ───────── ───────── ───────── ───────── ↓↓↓↓↓↓ ↓↓↓↓↓↓ ↓↓↓↓↓↓ ↓↓↓↓↓↓ F2s ───────── ───────── ───────── ───────── ↓↓↓↓↓↓ ↓↓↓↓↓↓ ↓↓↓↓↓↓ ↓↓↓↓↓↓ O2p ─ ─ ─ ─ ─ ─ ─ ─ ↑↑↓↓* + ↓↓↑↑* + ↑↑↑↑ + ↓↓↓↓ F2p ─ ─ ─ ─ ─ ─ ─ ─ ↓↓↓↓↓↓ ↓↓↓↓↓↓ ↓↓↓↓↓↓ ↓↓↓↓↓↓ S3s ───────── ───────── ───────── ───────── ↓↓↓↓↓↓ ↓↓↓↓↓↓ ↓↓↓↓↓↓ ↓↓↓↓↓↓ S3p ─ ─ ─ ─ ─ ─ ─ ─ ─ ─ ↑↑↓↓* + ↓↓↑↑* + ↑↑↑↑ + ↓↓↓↓ ↑↑↓↓ - ↓↓↑↑ - ↑↑↑ - ↓↓↓↓ The highest-energy orbital containing electrons is the antibonding σ* orbital between the O 2p and F 2p orbitals. There are 5 electrons in antibonding orbitals and 16 in bonding orbitals, so the bond order is: Bond order = 1/2 x (number of bonding electrons - number of antibonding electrons) = 1/2 x (16 - 5) = 5/2 = 2.5 Therefore, OF⁺ can exist with a bond order of 2.5.

Draw the Molecular Orbital Diagram of OF+ to Determine the Bond

Draw the Molecular Orbital Diagram of OF⁺ to Determine the Bond