Consider the bolded protons in 1-propanol.
$\mathrm { H } _ { 3 } \mathrm { C } - \mathrm { CH } _ { 2 } - \mathrm { CH } _ { 2 } - \mathrm { OH }$ Following a "D₂O shake," the splitting of the 1-propanol protons shown in bold type should be observed as

Question

Consider the bolded protons in 1-propanol.

\mathrm { H } _ { 3 } \mathrm { C } - \mathrm { CH } _ { 2 } - \mathrm { CH } _ { 2 } - \mathrm { OH }

Following a "D₂O shake," the splitting of the 1-propanol protons shown in bold type should be observed as

Quizplus · Accepted Answer

The protons on the second carbon (CH2) are adjacent to another CH2 group, which has 2 protons. According to the n+1 rule, where n is the number of neighboring protons, these protons will be split into n+1 peaks, making it a triplet (2+1=3).

Consider the Bolded Protons in 1-Propanol H3C−CH2−CH2−OH\mathrm { H } _ { 3 } \mathrm { C } - \mathrm { CH } _ { 2 } - \mathrm { CH } _ { 2 } - \mathrm { OH }H3​C−CH2​−CH2​−OH

Consider the Bolded Protons in 1-Propanol $\mathrm { H } _ { 3 } \mathrm { C } - \mathrm { CH } _ { 2 } - \mathrm { CH } _ { 2 } - \mathrm { OH }$