The frequency of color blindness (dyschromatopsia) in the Caucasian American male population is estimated to be about 8%. Let's call X the number of color-blind individuals in a random sample of 8 Caucasian American males. The table gives the probability distribution for X.
?
?
$$\begin{array} { | l | l | l | l | l | l | l | l | l | l | }
\hline X & 0 & 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 \
\hline P ( X ) & 0.513 & 0.357 & 0.109 & 0.019 & 0.002 & 0.000 & 0.000 & 0.000 & 0.000 \
\hline
\end{array}$$ What is the probability of getting 2 or 3 color-blind individuals in the sample?

Question

The frequency of color blindness (dyschromatopsia) in the Caucasian American male population is estimated to be about 8%. Let's call X the number of color-blind individuals in a random sample of 8 Caucasian American males. The table gives the probability distribution for X.
?
?
$$\begin{array} { | l | l | l | l | l | l | l | l | l | l | } 
\hline X & 0 & 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 \
\hline P ( X ) & 0.513 & 0.357 & 0.109 & 0.019 & 0.002 & 0.000 & 0.000 & 0.000 & 0.000 \
\hline
\end{array}$$ What is the probability of getting 2 or 3 color-blind individuals in the sample?

Quizplus · Accepted Answer

To find the probability of getting 2 or 3 color-blind individuals in the sample, we need to add the probabilities of X=2 and X=3: 
P(X=2) + P(X=3) = 0.109 + 0.019 = 0.128

Therefore, the answer is choice B.

The Frequency of Color Blindness (Dyschromatopsia) in the Caucasian American