A cricketer (mass = 85 kg) leaps up to catch a ball (mass = 0.16 kg) travelling to the boundary at 27 m/s. Assuming the catch is successful what is horizontal velocity of the player and ball immediately after the catch is taken, before the player lands on the ground?

Question

Quizplus · Accepted Answer

As momentum (M) = mass (m) × velocity (v), the velocity of the system (i.e. ball and player) can be found by rearranging this equation, i.e. v= M/m = 4.32/85.16 = 0.05 m/s.

A Cricketer (Mass = 85 Kg) Leaps Up to Catch