An 80 kg athlete is standing with his weight evenly distributed over 0.013 m² contact area under each foot. What is the pressure under one of his feet?

Question

Quizplus · Accepted Answer

Using the equation: Pressure (N/m²) = Force (N) / Area (m²) As weight is evenly distributed over two feet, weight (force) should be halved (i.e. (80 × 9.81)/2 = 392.4 N); hence: Pressure = 392.4 / 0.013 Pressure = 30184.6 N/m² or 30.185 kPa

An 80 Kg Athlete Is Standing with His Weight Evenly