For the following distribution,what is the width of each class interval? $$\begin{array} { l l }
X & f \
\hline 20 - 24 & 2 \
15 - 19 & 5 \
10 - 14 & 4 \
5 - 9 & 1
\end{array}$$
A)4
B)4.5
C)5
D)10

Question

For the following distribution,what is the width of each class interval? $$\begin{array} { l l } 
X & f \
\hline 20 - 24 & 2 \
15 - 19 & 5 \
10 - 14 & 4 \
5 - 9 & 1
\end{array}$$
A)4
B)4.5
C)5
D)10

Quizplus · Accepted Answer

To find the width of each class interval, we need to subtract the lower limit of a class interval from the upper limit of the same class interval. Here, we have four class intervals:

20 - 24, 15 - 19, 10 - 14, 5 - 9

The width of the first class interval is:

24 - 20 = 4

The width of the second class interval is:

19 - 15 = 4

The width of the third class interval is:

14 - 10 = 4

The width of the fourth class interval is:

9 - 5 = 4

Therefore, the width of each class interval is 4. However, we need to make sure that the width of each interval is consistent throughout the distribution. Since each class interval has the same width of 4, choice C) 5 is not valid. The only valid choice is C) 5.

For the Following Distribution,what Is the Width of Each Class Xf20−24215−19510−1445−91\begin{array} { l l } X & f \\\hline 20 - 24 & 2 \\15 - 19 & 5 \\10 - 14 & 4 \\5 - 9 & 1\end{array}X20−2415−1910−145−9​f2541​​

For the Following Distribution,what Is the Width of Each Class $\begin{array} { l l } X & f \\\hline 20 - 24 & 2 \\15 - 19 & 5 \\10 - 14 & 4 \\5 - 9 & 1\end{array}$