For the scores in the following frequency distribution table,the mean is M = 3.
$$\begin{array} { l l }
X & f \
\hline 4 & 1 \
3 & 4 \
2 & 2
\end{array}$$

Question

For the scores in the following frequency distribution table,the mean is M = 3.
 $$\begin{array} { l l } 
X & f \
\hline 4 & 1 \
3 & 4 \
2 & 2
\end{array}$$

Quizplus · Accepted Answer

To calculate the mean, we need to use the formula:

M = (ΣX * f) / Σf

ΣX * f = (4*1) + (3*4) + (2*2) = 18

Σf = 1 + 4 + 2 = 7

M = 18 / 7 = 2.57

Therefore, the statement is false, as the mean is not equal to 3.

For the Scores in the Following Frequency Distribution Table,the Mean Xf413422\begin{array} { l l } X & f \\\hline 4 & 1 \\3 & 4 \\2 & 2\end{array}X432​f142​​

For the Scores in the Following Frequency Distribution Table,the Mean $\begin{array} { l l } X & f \\\hline 4 & 1 \\3 & 4 \\2 & 2\end{array}$