Two samples,each with n = 4 scores,have a pooled variance of 32.The estimated standard error for the sample mean difference is √8.

Question

Quizplus · Accepted Answer

The estimated standard error for the sample mean difference can be calculated using the formula:

SE = √[(s1^2/n1) + (s2^2/n2)]

where s1^2 and s2^2 are the variances of the two samples and n1 and n2 are the sample sizes.

Given that the pooled variance is 32, we can estimate the individual variances as:

s1^2 = s2^2 = 32/2 = 16

Also, we are given that the sample size is n = 4 for both samples.

Substituting these values, we get:

SE = √[(16/4) + (16/4)]
   = √8

Therefore, the estimated standard error for the sample mean difference is √8, which means that the statement is true.

Two Samples,each with N = 4 Scores,have a Pooled Variance