If a set of n = 9 difference scores has a mean of MD = 3.5 and a variance of s² = 36,then the standard error for the sample mean difference is 4 points.

Question

Quizplus · Accepted Answer

The formula for the standard error of the mean difference is:

SEMD = s/√n

where s is the standard deviation of the difference scores and n is the sample size.

To find the standard deviation, we first need to take the square root of the variance:

s = √(s²) = √36 = 6

Then, plugging in the given values:

SEMD = 6/√9 = 6/3 = 2

Therefore, the statement "the standard error for the sample mean difference is 4 points" is false.

If a Set of N = 9 Difference Scores Has