For a material with a tensile modulus of elasticity of 200 GPa, the strain produced by a stress of 50 MPa, assuming the limit of proportionality is not exceeded, will be:
A) 0.000 25
B) 0.25
C) 4
D) 4000

Question

Quizplus · Accepted Answer

The relationship between stress (σ), strain (ε), and modulus of elasticity (E) is given by the equation:

σ = Eε

We are given E = 200 GPa (or 200 x 10^9 Pa) and σ = 50 MPa (or 50 x 10^6 Pa).

Plugging these values into the equation, we get:

50 x 10^6 = 200 x 10^9 ε

Solving for ε, we get:

ε = (50/200) x 10^-3 = 0.00025

Therefore, the strain produced by a stress of 50 MPa is 0.00025, which corresponds to answer choice A.

For a Material with a Tensile Modulus of Elasticity of 200