If a purely-resistive branch of a parallel circuit draws a current of 5 A when supplied with a voltage of 100 V, then its _________ must be __________.
A) admittance, 20 mho
B) susceptance, 0.05 ohm.
C) conductance, 0.05 siemens
D) conductivity, 20 siemens.

Question

Quizplus · Accepted Answer

According to Ohm's Law, the conductance (G) of a purely resistive element is equal to the current (I) divided by the voltage (V), or G = I/V. In this case, G = 5 A / 100 V = 0.05 S (siemens), which is the same as choice C. Choices A, B, and D are incorrect because they relate to other electrical properties (admittance, susceptance, conductivity) that are not relevant for a purely resistive element.

If a Purely-Resistive Branch of a Parallel Circuit Draws a Current