Assume that you are especially interested in DUI offenders (2013) with extensive prior traffic violations (5+) other than parking infractions. Assume that records indicate that 6 of the 50 DUI offenders have 5+ prior traffic violations. These 6 individuals represent your new population. The numbers of traffic offenses (prior to the DUI in 2013) for each individual are 5, 11, 7, 9, 6, and 10. Assume that we want to draw a sample of 3 individuals.
a. How many unique samples can be drawn with n = 6 and n = 3?
b. What is the mean of each individual sample? What is the standard deviation of each individual sample?
c. Find the mean of means and the standard error of the sampling distribution.
d. What are the mean and the standard deviation of the entire population?
e. Calculate the standard error.

Question

Quizplus · Accepted Answer

The Answer is a. Use formula 5-1:

\begin{aligned}C & = \frac { N ! } { n ! ( N - n ) ! } \C & = \frac { 6 ! } { 3 ! ( 6 - 3 ) ! } = 20\end{aligned}

b.
$a. Use formula 5-1: \begin{aligned} C & = \frac { N ! } { n ! ( N - n ) ! } \ C & = \frac { 6 ! } { 3 ! ( 6 - 3 ) ! } = 20 \end{aligned} b. c. Mean of means = 8.00; standard error of sampling distribution = 2.28. d. Population mean = 8.00; standard deviation (population) = 2.37. ext { e. Standard error } = \frac { s } { \sqrt { n } } = \frac { 2.28 } { \sqrt { 3 } } = 1.316$
c. Mean of means = 8.00; standard error of sampling distribution = 2.28.
d. Population mean = 8.00; standard deviation (population) = 2.37.

ext { e. Standard error } = \frac { s } { \sqrt { n } } = \frac { 2.28 } { \sqrt { 3 } } = 1.316

Assume That You Are Especially Interested in DUI Offenders (2013)