Given a triangle with sides a = 20 feet, b = 40 feet, and c = 56, what is the area in square feet?

Name: Given a triangle with sides a = 20 feet, b = 40 feet, and c = 56, what is the area in square feet?
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The area of the triangle is 281.68 ft². Solution Use the formula for the area of a triangle with sides a, b, and c: A = [s(s-a)(s-b)(s-c)]^½ where s = (a + b + c)/2 Where a = 20 ft b = 40 ft c = 56 ft s = (20 ft + 40 ft + 56 ft)/2 = 58 ft A = [58 (58-20)(58 - 40)(58 - 56)]^½= 281.68 ft²

Given a Triangle with Sides a = 20 Feet, B