Calculate the change in entropy of the following equation:
FeCl₃_(s) + 3Na_(s) --> Fe_(s) + 3NaCl_(s)

Question

Calculate the change in entropy of the following equation: FeCl₃_(s) + 3Na_(s) --> Fe_(s) + 3NaCl_(s)

Quizplus · Accepted Answer

Solution is as follows: DS_rxn° = DSproducts° - DSreactants° Students must look up the DS° for each product and reactant. The numbers are as follows: DS° (FeCl₃ _(s) ) = 142.3 J/mol K DS° (Na_(s) ) = 51.3 J/mol K DS° (Fe_(s) ) = 27.2 J/mol K DS° (NaCl_(s) ) = 72.3 J/mol K Therefore DS_rxn° = [(1mol * 27.2 J/mol K) + (3mol * 72.3 J/mol K) ] - [ (1mol * 142.3 J/mol K) +(3mol * 51.3 J/mol K)] DS_rxn° = -52.1 J/K ***mole amounts come from the stoichiometry

Calculate the Change in Entropy of the Following Equation