If a magnetic field of 10 x 10-5 T is applied perpendicularly to a 1 meter wire carrying 5 amps of current, what will be the force experienced by the wire?
A)0)0000085 N
B)0)00005 N
C)0)095 N
D)0)135 N
E)0)875 N

Question

Quizplus · Accepted Answer

The force experienced will be 0.00005 N. The force generated by a magnetic field on a current carrying wire is F = I*L*B*sin(?). Because the field is perpendicular, sin(?) is 1. Thus, F = 5*1*10x10-5, or approximately 0.00005 Newtons.

If a Magnetic Field of 10 X 10-5 T Is