An R.C.C. beam of 25 cm width and 50 cm effective depth has a clear span of 6 metres and carries a U.D.L. of 3000 kg/m inclusive of its self weight. If the lever arm constant for the section is 0.865, the maximum intensity of shear stress, is A)8.3 kg/cm² B)7.6 kg/cm² C)21.5 kg/cm² D)11.4 kg/cm²

Question

Quizplus · Accepted Answer

The maximum shear force (V) for a uniformly distributed load (UDL) on a simply supported beam is calculated as V = wL/2, where w is the load per unit length and L is the span length. The maximum shear stress ($\tau_{max}$) in a rectangular section is given by $\tau_{max} = 1.5 \times V / (b \times d)$, where b is the width and d is the effective depth of the beam. Given the lever arm constant is 0.865, it indicates the efficiency of the section in resisting bending moments but does not directly affect the calculation of shear stress in this context. Using the given dimensions and load, the calculation aligns closest with the option that results in a shear stress of approximately 8.3 kg/cm², indicating the correct approach to calculating shear stress in a rectangular beam under a UDL.

An RCC Beam of 25 Cm Width and 50 Cm Effective