If initial velocity of an object is zero, then distance covered by it in time t and acceleration of 9.8ms^-2 would be A)2.9t² B)3t² C)4t² D)4.9t²

Question

Quizplus · Accepted Answer

The distance covered by an object under uniform acceleration can be calculated using the formula $s = ut + \frac{1}{2}at^2$, where $s$ is the distance, $u$ is the initial velocity, $a$ is the acceleration, and $t$ is the time. Given $u = 0$ and $a = 9.8 \, \text{m/s}^2$, substituting these values gives $s = 0 + \frac{1}{2} \times 9.8 \times t^2 = 4.9t^2$, which matches option D.

If Initial Velocity of an Object Is Zero, Then Distance