Attenuation coefficient of bone is 600 m^-1 for x-rays of energy 20 keV and intensity of beam of x-rays is 20 Wm^-2, then intensity of beam after passingthrough a bone of 4mm is {{}} A)3 Wm^-2 B)2.5 Wm^-2 C)2.0 Wm^-2 D)1.8 Wm^-2

Question

Quizplus · Accepted Answer

The intensity of the beam after passing through a material can be calculated using the formula $I = I_0 e^{-\mu x}$, where $I$ is the final intensity, $I_0$ is the initial intensity, $\mu$ is the attenuation coefficient, and $x$ is the thickness of the material. Given $I_0 = 20 \, \text{W/m}^2$, $\mu = 600 \, \text{m}^{-1}$, and $x = 4 \, \text{mm} = 0.004 \, \text{m}$, we find $I = 20 \times e^{-600 \times 0.004} = 1.8 \, \text{W/m}^2$.

Attenuation Coefficient of Bone Is 600 M-1 for X-Rays of Energy

Attenuation Coefficient of Bone Is 600 M^-1 for X-Rays of Energy