Hartley oscillator has inductance values of 12 mH and 4 mH in the feedback section and a capacitor of 4 nF. Then the resonant frequency of the circuit is:
A)19.89 khz
B)25 khz
C)45 khz
D)12 khz

Question

Quizplus · Accepted Answer

The resonant frequency $f$ of a Hartley oscillator can be calculated using the formula $f = \frac{1}{2\pi\sqrt{L_{total}C}}$, where $L_{total}$ is the total inductance in the circuit and $C$ is the capacitance. For a Hartley oscillator, the total inductance $L_{total}$ is the sum of the individual inductances, so $L_{total} = 12\,mH + 4\,mH = 16\,mH = 16 \times 10^{-3}\,H$, and $C = 4\,nF = 4 \times 10^{-9}\,F$. Plugging these values into the formula gives $f = \frac{1}{2\pi\sqrt{16 \times 10^{-3} \times 4 \times 10^{-9}}}$, which calculates to approximately 19.89 kHz.

Hartley Oscillator Has Inductance Values of 12 MH and 4