In the equivalent circuit of a quartz crystal, LCR arm has an inductance of 4 mH and capacitor has a value of 4nF, then the series resonant frequency of the oscillator is:
A)0.25 mhz
B)2.5 mhz
C)25 mhz
D)5 mhz

Question

Quizplus · Accepted Answer

The series resonant frequency of an LCR circuit is given by:$$f_r = \frac{1}{2\pi\sqrt{LC}}$$Substituting the given values, we get:$$f_r = \frac{1}{2\pi\sqrt{(4	ext{ mH})(4	ext{ nF})}} = 0.25	ext{ MHz}$$

In the Equivalent Circuit of a Quartz Crystal, LCR Arm