A perfect engine works on the Carnot cycle between 727 °C and 227°C. The efficiency of the engine is

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Quizplus · Accepted Answer

The efficiency ($\eta$) of a Carnot engine is given by $\eta = 1 - \frac{T_c}{T_h}$, where $T_c$ and $T_h$ are the cold and hot reservoir temperatures respectively, in Kelvin. To convert °C to K, add 273.15 to each temperature. Thus, $T_h = 727 + 273.15 = 1000.15 K$ and $T_c = 227 + 273.15 = 500.15 K$. Plugging these into the formula gives $\eta = 1 - \frac{500.15}{1000.15} = 0.5$.

A Perfect Engine Works on the Carnot Cycle Between 727