Which is True about SR and RR-conflict:
A)If there is no SR-conflict in CLR(1) then definitely there will be no SR-conflict in LALR(1).
B)RR-conflict might occur if lookahead for final items(reduce-moves) is same.
C)Known that CLR(1) has no RR-conflict, still RR-conflict might occur in LALR(1).
D)All of the above.

Question

Quizplus · Accepted Answer

All the statements are true regarding SR and RR-conflicts in the context of CLR(1) and LALR(1) parsers. A) is true because LALR(1) parsers are constructed by merging states of the CLR(1) automaton that have the same core, which can lead to fewer SR-conflicts than in CLR(1). B) is true because RR-conflicts occur when two rules are reducible in the same state with the same lookahead, which is a direct consequence of having the same lookahead for final items. C) is true because the process of merging states in LALR(1) can introduce RR-conflicts that were not present in CLR(1), due to the combination of lookaheads from different states.

Which Is True About SR and RR-Conflict