What is the approximate distance traveled by a vehicle decelerating from 65 miles per hour (mph) to 35 mph at a rate of 3 feet per second/second?

Question

Quizplus · Accepted Answer

The approximate distance traveled by a vehicle decelerating from 65 miles per hour (mph) to 35 mph at a rate of 3 feet per second/second is 1,070 feet. Solution: use the distance traveled equation x = v_f² - v_o² / 2a Where v_f = 65 mph * (5280 feet/mile) (1 hour/3600 seconds) = 95 feet per second v_o = 35 mph * (5280 feet/mile) (1 hour/3600 seconds) = 51 feet per second a = 3 feet/second/second x = (95² - 51²)/ 2(3) x = 1,070 feet (approximate)

What Is the Approximate Distance Traveled by a Vehicle Decelerating