Using the ideal gas equation, find the pressure of 22.4L of helium at 273K when n=1.00 mol. Adjust this calculation using the real gas equation to find the actual pressure. What are the ideal and real pressures?

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Quizplus · Accepted Answer

Solution is as follows: PV=nRT P=pressure (atm) V=volume (22.4L) n=amount (1 mol) R = constant (0.08206 L*atm/mol*K) T = temperature (273K) Ideal gas equaion gives P=1.0atm a=0.03412 (L²*atm/moL²) b= 0.02370 (L/mol) (P+(an²/V²))(V-nb)=nRT By substituting in the known values of V, n, R, and T, you solve for P=1.001atm, or 1.00atm with significant figures.

Using the Ideal Gas Equation, Find the Pressure of 22