In a reversible cycle, the source temperature is 227°C & the sink temperature is 27°C. The maximum available work for a heat input of 100 kJ will be

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Quizplus · Accepted Answer

The maximum work in a reversible cycle is given by the formula: $W_{max} = Q(1 - \frac{T_{sink}}{T_{source}})$, where $Q$ is the heat input, $T_{source}$ and $T_{sink}$ are the source and sink temperatures in Kelvin, respectively. Convert temperatures to Kelvin: $T_{source} = 227 + 273 = 500K$, $T_{sink} = 27 + 273 = 300K$. Thus, $W_{max} = 100(1 - \frac{300}{500}) = 100 \times 0.4 = 40$ kJ.

In a Reversible Cycle, the Source Temperature Is 227°C