The probability that a participant is married is p(M)= .60.The probability that a participant is married and "in love" is p(M$\cap$L)= .46.Thus,the probability that a participant is in love,given that the participant is married,is p = .77.

Question

Quizplus · Accepted Answer

This follows from Bayes' theorem. Using notation P(A|B) to mean "the probability of A given B", we have:

P(in love | married) = P(married and in love) / P(married)

Plugging in the numbers given, we get:

P(in love | married) = 0.46 / 0.6 = 0.77

This matches the probability given in the problem statement, so the answer is true.

The Probability That a Participant Is Married Is P(M)= ∩\cap∩ L)= 46Thus,the Probability That a Participant Is in Love,given That the Probability

The Probability That a Participant Is Married Is P(M)= $\cap$ L)= 46Thus,the Probability That a Participant Is in Love,given That the Probability