A researcher determines that students are active about 60 ± 12 (M ± SD)min/day.Assuming these data are normally distributed,what is the z score for students being active 48 min/week?
A) 1.0
B) -1.0
C) 0
D) There is not enough information to answer this question.

Question

Quizplus · Accepted Answer

To find the z-score, we first need to convert the 48 minutes/week to minutes/day:
48/7 = 6.86 minutes/day

Then we use the formula:

z = (x - M) / SD

where x is the value we want to convert to a z-score, M is the mean, and SD is the standard deviation.

z = (6.86 - 60) / 12
z = -4.261

Therefore, the z-score for students being active 48 min/week is -4.261, which corresponds to answer choice B (-1.0).

A Researcher Determines That Students Are Active About 60 ±