The rate of heat loss through a furnace wall is 1000 kcal per hour when inside temperature is 1000°C and outside wall temperature is 500°C. What should be the wall thickness in case the thermal conductivity of wall material is 0.5 kcal/m-hr°C

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The rate of heat loss through a furnace wall is given by the equation:Q = kA(T1 - T2)/dwhere:Q is the rate of heat loss (kcal/hr)k is the thermal conductivity of the wall material (kcal/m-hr°C)A is the surface area of the wall (m2)T1 is the inside temperature (°C)T2 is the outside wall temperature (°C)d is the wall thickness (m)In this problem, we are given the following information:Q = 1000 kcal/hrk = 0.5 kcal/m-hr°CT1 = 1000°CT2 = 500°CWe need to find the wall thickness, d.Rearranging the equation above, we get:d = kA(T1 - T2)/QSubstituting the given values into the equation, we get:d = (0.5 kcal/m-hr°C)(A)(1000°C - 500°C)/(1000 kcal/hr)Simplifying, we get:d = 0.25ASince we do not know the surface area of the wall, we cannot find the exact value of d. However, we can say that the wall thickness is proportional to the surface area. Therefore, the correct answer is A) 25 cm, which is the smallest value given in the choices.

The Rate of Heat Loss Through a Furnace Wall Is