In RSA, ?(n) = in terms of p and q
A)(p)/(q)
B)(p)(q)
C)(p-1)(q-1)
D)(p+1)(q+1)

Name: In RSA, ?(n) = in terms of p and q A)(p)/(q) B)(p)(q) C)(p-1)(q-1) D)(p+1)(q+1)
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Quizplus · Accepted Answer

In RSA, $ \phi(n) $ is calculated as $ (p-1)(q-1) $, where $ p $ and $ q $ are prime numbers. This is because $ \phi(n) $ represents the number of integers less than $ n $ that are coprime to $ n $, and for a product of two distinct prime numbers $ p $ and $ q $, this value is $ (p-1)(q-1) $.

In RSA, ?(N) = in Terms of P and Q