A transistor has hie =1K? and hfe=60 with an bypassed emitter resistor Re=1k?. What will be the input resistance and output resistance?
A)90k? and 50k? respectively
B)33k? and 45k? respectively
C)6k? and 40k? respectively
D)63k? and 40k? respectively

Question

Quizplus · Accepted Answer

The input resistance (Rin) of a transistor with an emitter bypass can be calculated using the formula Rin = hie + (hfe + 1)Re. Substituting the given values, Rin = 1000 + (60 + 1) * 1000 = 61kΩ. The output resistance (Rout) is not directly given, but assuming a common emitter configuration without any additional details, the output resistance is primarily determined by the collector resistor (not given), making the calculation for Rout not straightforward from the provided information. However, given the options and typical configurations, the closest match and a common assumption for Rout in a simplified analysis would be around 40kΩ, considering the internal transistor resistance and ignoring external circuit elements.

A Transistor Has Hie =1K? and Hfe=60 with an Bypassed