If w is width of sleepers, s is sleeper spacing and d is depth of ballast then
A) d = (s - w) /2
B) d = (s - w) /3
C) d = (s - w) /4
D) d = (s - w) /5
Correct Answer:
Verified
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A)Rectangular is cross section throughout
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A)Minimum distance
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(ii. Home
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A)Chir
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C)Sal
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