What is the volume of 0.25 mol of ammonia gas (NH₃) at 1.00 atmand 273 K?

Question

Quizplus · Accepted Answer

The volume of a gas can be calculated using the ideal gas law, PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant (0.0821 L·atm/(mol·K)), and T is the temperature in Kelvin. Given that n = 0.25 mol, P = 1.00 atm, and T = 273 K, substituting these values into the ideal gas law gives V = (0.25 mol)(0.0821 L·atm/(mol·K))(273 K) / (1.00 atm) = 5.6 L.

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