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Question 13
Use integration by parts to evaluate the integral ∫xx+8dx\int \frac { x } { \sqrt { x + 8 } } d x∫x+8xdx .
A) 23(x−8) 1/2(x+16) +C\frac { 2 } { 3 } ( x - 8 ) ^ { 1 / 2 } ( x + 16 ) + C32(x−8) 1/2(x+16) +C B) 23(x+8) 1/2(x−16) +C\frac { 2 } { 3 } ( x + 8 ) ^ { 1 / 2 } ( x - 16 ) + C32(x+8) 1/2(x−16) +C C) 32(x+8) 1/2(x−16) +C\frac { 3 } { 2 } ( x + 8 ) ^ { 1 / 2 } ( x - 16 ) + C23(x+8) 1/2(x−16) +C D) 23(x+8) 3/2(x−16) +C\frac { 2 } { 3 } ( x + 8 ) ^ { 3 / 2 } ( x - 16 ) + C32(x+8) 3/2(x−16) +C
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