$f ( x ) = \left\{ \begin{array} { l l }
\frac { 5 } { x ^ { 6 } } & \text { if } x \geq 1 \
0 & \text { if } x

Question

$f ( x ) = \left\{ \begin{array} { l l } 
\frac { 5 } { x ^ { 6 } } & \text { if } x \geq 1 \
0 & \text { if } x < 1
\end{array} \right.$ is a probability density function for a particular random variable X. Use integration to find $P ( X \geq 3 )$

Quizplus · Accepted Answer

The Answer of $f ( x ) = \left\{ \begin{array} { l l } 
\frac { 5 } { x ^ { 6 } } & \text { if } x \geq 1 \
0 & \text { if } x < 1
\end{array} \right.$ is a probability density function for a particular random variable X. Use integration to find $P ( X \geq 3 )$

f(x)={5x6 if x≥10 if x<1f ( x ) = \left\{ \begin{array} { l l } \frac { 5 } { x ^ { 6 } } & \text { if } x \geq 1 \\0 & \text { if } x < 1\end{array} \right.f(x)={x65​0​ if x≥1 if x<1​

$f ( x ) = \left\{ \begin{array} { l l } \frac { 5 } { x ^ { 6 } } & \text { if } x \geq 1 \\0 & \text { if } x < 1\end{array} \right.$