Evaluate $\int _ { - 2 } ^ { 2 } \left( x ^ { 5 } + 3 x ^ { 3 } - 2 x \right) d x$ . Round answer to three decimal places, if necessary.
A) 50.123
B) 4
C) 0
D) 6.892

Question

Quizplus · Accepted Answer

The integral of an odd function over a symmetric interval around zero is zero. The function $x^5 + 3x^3 - 2x$ is odd because all powers of $x$ are odd, and the interval is symmetric around zero (-2 to 2).

Evaluate ∫−22(x5+3x3−2x)dx\int _ { - 2 } ^ { 2 } \left( x ^ { 5 } + 3 x ^ { 3 } - 2 x \right) d x∫−22​(x5+3x3−2x)dx

Evaluate $\int _ { - 2 } ^ { 2 } \left( x ^ { 5 } + 3 x ^ { 3 } - 2 x \right) d x$