= The absolute maximum of the function $f ( x ) = x ^ { 4 } - 2 x ^ { 2 } + 3$ on the interval -1 $\le$ x $\le$ 2 is 11.

Question

= The absolute maximum of the function $f ( x ) = x ^ { 4 } - 2 x ^ { 2 } + 3$ on the interval -1 $\le$  x $\le$  2 is 11.

Quizplus · Accepted Answer

The absolute maximum of the function $f ( x ) = x ^ { 4 } - 2 x ^ { 2 } + 3$ on the interval -1 $\le$  x $\le$  2 is 11. This can be verified by finding the critical points of the function and evaluating the function at those points and the endpoints of the interval.

= the Absolute Maximum of the Function f(x)=x4−2x2+3f ( x ) = x ^ { 4 } - 2 x ^ { 2 } + 3f(x)=x4−2x2+3

= the Absolute Maximum of the Function $f ( x ) = x ^ { 4 } - 2 x ^ { 2 } + 3$