Differentiating $f ( x ) = \frac { 1 } { 5 } x ^ { 6 } - 3 x ^ { 4 } + 2 x - 4$ gives $\frac { 6 } { 5 } x ^ { 5 } - 12 x ^ { 3 } + 2$ .

Name: Differentiating $f ( x ) = \frac { 1 } { 5 } x ^ { 6 } - 3 x ^ { 4 } + 2 x - 4$ gives $\frac { 6 } { 5 } x ^ { 5 } - 12 x ^ { 3 } + 2$ .
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Differentiating $f(x) = \frac{1}{5}x^6 - 3x^4 + 2x - 4$ term by term using the power rule $d/dx[x^n] = nx^{n-1}$ gives $\frac{6}{5}x^5 - 12x^3 + 2$, as the derivative of a constant term (-4) is 0.

Differentiating f(x)=15x6−3x4+2x−4f ( x ) = \frac { 1 } { 5 } x ^ { 6 } - 3 x ^ { 4 } + 2 x - 4f(x)=51​x6−3x4+2x−4

Differentiating $f ( x ) = \frac { 1 } { 5 } x ^ { 6 } - 3 x ^ { 4 } + 2 x - 4$